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Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for “abcabcbb” is “abc”, which the length is 3. For “bbbbb” the longest substring is “b”, with the length of 1.

思路一：

981 / 981 test cases passed.

Status: Accepted

Runtime: 604 ms

借用队列的方法，想象下推箱子

import Queueclass Solution(object):    def lengthOfLongestSubstring(self, s):        q=Queue.Queue(maxsize=0)        count=[]        list_=[]        if len(s)==0:            return 0        for i in range(len(s)):            if s[i] not in list_:                q.put(s[i])                list_.append(s[i])            else:                count.append(q.qsize())                flag=1                while flag:                    value=q.get()                    if value==s[i]:                        flag=0                    else:                        list_.remove(value)                q.put(s[i])        count.append(q.qsize())        return max(count)

思路二：

标记位置，遍历字符串s，index=max(index,doc[s[i]]+1),doc[s[i]]=i,

981 / 981 test cases passed.

Status: Accepted

Runtime: 112 ms

Submitted: 0 minutes ago

class Solution(object):    def lengthOfLongestSubstring(self, s):        if len(s)==0:            return 0        max_=0        dic={}        index=0        if len(s)==0:            return 0        for i in range(len(s)):            if s[i] not in dic:                dic.setdefault(s[i],i)            else:                max_=max(max_,i-index)                index=max(index,dic[s[i]]+1)                dic[s[i]]=i        max_=max(max_,len(s)-index)        return max_

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